严重: Error listenerStart
悬赏：5 发布时间：2008-07-20 提问人：ＫｉｎＧ (初级程序员)
错误
严重: Error listenerStart
2008-7-20 2:17:09 org.apache.catalina.core.StandardContext start
严重: Context [/sshj] startup failed due to previous errors
写了一个测试类
public class TextUtil {
public static void main(String[] args) {
ApplicationContext context = new FileSystemXmlApplicationContext(
"src/applicationContext.xml");
context.getBean("sessionFactory");
// new ClassPathXmlApplicationContext("applicationContext.xml").getBean("sessionFactory");
}
}
没有任何错误.所有的Bean都测试了。
WEB.XML
*****************************
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
WEB-INF/classes/applicationContext.xml
</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListene
</listener-class>
</listener>
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>
org.apache.struts.action.ActionServlet
</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>3</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>3</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
严重: Error listenerStart
2008-7-20 2:17:09 org.apache.catalina.core.StandardContext start
严重: Context [/sshj] startup failed due to previous errors
写了一个测试类
public class TextUtil {
public static void main(String[] args) {
ApplicationContext context = new FileSystemXmlApplicationContext(
"src/applicationContext.xml");
context.getBean("sessionFactory");
// new ClassPathXmlApplicationContext("applicationContext.xml").getBean("sessionFactory");
}
}
没有任何错误.所有的Bean都测试了。
WEB.XML
*****************************
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
WEB-INF/classes/applicationContext.xml
</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListene
</listener-class>
</listener>
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>
org.apache.struts.action.ActionServlet
</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>3</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>3</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
采纳的答案
2008-07-20 ag_sherry (中级程序员)
我以前遇到过，是因为jar包冲突，你去你的日志里面好好看看，有相关的提示!
提问者对于答案的评价：
我自己写了org.apache.struts.action.MyActionServlet
忘记+进去了
额外加分：5
